PHP如何在数据库中插入NULL？

Question

I have a normal HTML-File that give a string via. POST to my PHP-file wich will put this to a MySQL-database.

How do I achieve that I can write a "real" NULL in the database and not " " (a empty string) or something like that?

The MySQL column is nullable.

My form:

<form method="post" action="putInDatabase.php">

    <label>Text</label>
    <textarea name="text" ></textarea>

    <label>Picture URL (optional)</label>
    <input name="image" />
    <br>

    <input id="submit" name="submit" type="submit" value="submit">

</form>

My PHP-File:

<?php

  $text = "";
  $image = null;

  if (isset($_POST["submit"]))
  {
    $text = $_POST["text"];

    $image = $_POST["image"];
  }

  $text = strtr ($text, array ('"' => '\"'));


  $con = mysql_connect("censored :)");

  if (!$con)
  {
    die('ERROR' . mysql_error());
  }
  mysql_select_db("_DATABASE_HERE_", $con);


  $insertSQL = "INSERT INTO `_DATABASE_HERE_`.`_NAME_HERE_` (`Text`, `PictureURL`) VALUES ('$text', '$image ');";  

  $res = mysql_query($insertSQL); 
  $res = mysql_query($sql);

  mysql_close($con);

  echo "Success!";

?>

Answer 1

You'd need to pre-process your text. And since you're vulnerable to sql injection attacks this should be considered MANDATORY:

if (isset($_POST['text']) && !empty($_POST['text'])) {
   $safetext = "'" . mysql_real_escape_string($_POST['text']) . "'";
} else {
   $safetext = 'null';
}

$sql = "INSERT ... VALUES ($safetext, ...)";

Note how the quotes are added inside the if() . If there's some text to be done, the sql-escaped text is surrounded by quotes. if there's no text at all, then the string null is added in. This boils down to the difference between null and 'null' .

null is an sql null, "unknown value". 'null' is a string with the literal characters n , u , l , and l in it. In SQL terms, they're two completely different things.

The above code would produce

INSERT ... VALUES (null, ...)
INSERT ... VALUES ('Miles O\'Brien', ...)

Answer 2

Try this:

$variable_name = "NULL";

Now, while inserting into the database, use $variable_name.

That should do it.

EDIT: You need to either use prepare statements, if you are gonna switch to PDOs in future or escape the user input.