删除列表项中的引号

Question

I am running this program:

f = open( "animals.txt", "r")
g = f.read()
g1 = g.split(',') #turning the file into list
print g1

And I want this to come out:

['ELDEN', 'DORSEY', 'DARELL', 'BRODERICK', 'ALONSO']

Instead, I am getting this:

['"ELDEN"', '"DORSEY"', '"DARELL"', '"BRODERICK"', '"ALONSO"']

Does anyone know how to remove the inner quotes

Answer 1

You can easily strip off the quote characters using a list comprehension and str.strip :

f = open( "animals.txt", "r")
g = f.read()
g1 = [x.strip('"') for x in g.split(',')]
print g1

Demo:

>>> lst = ['"ELDEN"', '"DORSEY"', '"DARELL"', '"BRODERICK"', '"ALONSO"']
>>> [x.strip('"') for x in lst]
['ELDEN', 'DORSEY', 'DARELL', 'BRODERICK', 'ALONSO']
>>>

Answer 2

尝试使用列表理解，您可以有效地将列表重新分配为删除引号的等效列表。

g1 = [i.replace('"', '') for i in g1] # remove quote from each element

Answer 3

What is creating your file in the first place? It looks as though you have a kind of CSV where either all elements, or at least all string elements, are surrounded by quotation marks. As such, you have at least a couple of choices for moving the quotation-mark removal "upstream" from what most of the other answers here are suggesting:

1. Use the csv module :

 import csv with open('animals.txt', 'r') as f: g = csv.reader(f) g1 = g.next() 

2. Include the quotation marks in your split() , and chop off the leading and trailing quotes first:

 with open('animals.txt', 'r') as f: g = f.read() g1 = g[1:-1].split('","') 

The first option may be somewhat more "heavyweight" than what you're looking for, but it's more robust (and still not that heavy). Note that the second option assumes that your file does NOT have a trailing newline at the end. If it does, you have to adjust accordingly.

Answer 4

Maybe we should go back to the source.

Apparently your file contains the text "ELDEN", "DORSEY", "DARELL", "BRODERICK", "ALONSO" (etc). We can delegate the parsing:

import ast

with open("animals.txt") as inf:
    g1 = ast.literal_eval("[" + inf.read() + "]")