从字符串和列表中删除python输出中的引号

Question

I have to implement a function that takes a parameter of type string and parses this parameter and returns a tuple with the first value of the tuple being the number of units and the second value of the tuple the measurement unit. I was successful in splitting the number and measurement unit, but I need help with the quotation placement.

input_value = "3 ft"
split_list = (input_value.split())
print(split_list)
['3', 'ft']

How do I go about getting an output that looks like [3, "ft"] ?

Answer 1

input_value = "3 ft"
split_list = (input_value.split())
try:
    split_list[0] = int(split_list[0])
except ValueError:
    split_list[0] = float(split_list[0])
print(split_list) [3, 'ft']

Answer 2

You need to cast the first element of the split_list , ie, the three in your example to an int if you do not want quote marks around the number of units.

As for getting double quotes around the measurement unit, by default Python prints strings using single quotes, but you can use json. dumps as a workaround since JSON strings have to use double quotes:

import json

input_value = "3 ft"
split_list = input_value.split()
split_list[0] = int(split_list[0])
print(json.dumps(split_list))

Output:

[3, "ft"]

---

If you need to support decimals eg, 3.5 ft use float() instead of int() :

import json

input_value = "3.5 ft"
split_list = input_value.split()
split_list[0] = float(split_list[0])
print(json.dumps(split_list))

Output:

[3.5, "ft"]

Try it here .

Answer 3

Suggested

What you can do is to convert the value of the list using function . So, it will be hackable edited when ever you want to add more formating to it.

Code

List

alist = ['3', 'ft']

Function

def lista(alist):
    number, measure = alist
    number = int(number)
    alist = [number, measure]
    return alist

Calling Function

print(alist)
print("print the list after conversion {}".format(lista(alist)))

OUTPUT

['3', 'ft']
print the list after conversion [3, 'ft']