获取由lm（）返回的“ mlm”对象的回归系数的置信区间

Question

I'm running a multivariate regression with 2 outcome variables and 5 predictors. I would like to obtain the confidence intervals for all regression coefficients. Usually I use the function lm but it doesn't seem to work for a multivariate regression model (object mlm ).

Here's a reproducible example.

library(car)
mod <- lm(cbind(income, prestige) ~ education + women, data=Prestige)
confint(mod) # doesn't return anything.

Any alternative way to do it? (I could just use the value of the standard error and multiply by the right critical t value, but I was wondering if there was an easier way to do it).

Answer 1

This comes from the predict.lm example. You want the interval = 'confidence' option.

x <- rnorm(15)
y <- x + rnorm(15)
predict(lm(y ~ x))
new <- data.frame(x = seq(-3, 3, 0.5))
predict(lm(y ~ x), new, se.fit = TRUE)
pred.w.clim <- predict(lm(y ~ x), new, interval = "confidence")
matplot(new$x, pred.w.clim,
        lty = c(1,2,2,3,3), type = "l", ylab = "predicted y")

Answer 2

confint won't return you anything, because there is no "mlm" method supported:

methods(confint)
#[1] confint.default confint.glm*    confint.lm      confint.nls*  

As you said, we can just plus / minus some multiple of standard error to get upper / lower bound of confidence interval. You were probably going to do this via coef(summary(mod)) , then use some *apply method to extract standard errors. But my answer to Obtain standard errors of regression coefficients for an “mlm” object returned by lm() gives you a supper efficient way to get standard errors without going through summary . Applying std_mlm to your example model gives:

se <- std_mlm(mod)
#                 income   prestige
#(Intercept) 1162.299027 3.54212524
#education    103.731410 0.31612316
#women          8.921229 0.02718759

Now, we define another small function to compute lower and upper bound:

## add "mlm" method to generic function "confint"
confint.mlm <- function (model, level = 0.95) {
  beta <- coef(model)
  se <- std_mlm (model)
  alpha <- qt((1 - level) / 2, df = model$df.residual)
  list(lower = beta + alpha * se, upper = beta - alpha * se)
  }

## call "confint"
confint(mod)

#$lower
#                 income    prestige
#(Intercept) -3798.25140 -15.7825086
#education     739.05564   4.8005390
#women         -81.75738  -0.1469923
#
#$upper
#                income    prestige
#(Intercept)  814.25546 -1.72581876
#education   1150.70689  6.05505285
#women        -46.35407 -0.03910015

It is easy to interpret this. For example, for response income , the 95%-confidence interval for all variables are

#(intercept)    (-3798.25140, 814.25546)
#  education    (739.05564, 1150.70689)
#      women    (-81.75738, -46.35407)

Answer 3

This seems to have been discussed recently (July 2018) on the R-devel list , so hopefully by the next version of R it will be fixed. A workaround proposed on that list is to use:

confint.mlm <- function (object, level = 0.95, ...) {
  cf <- coef(object)
  ncfs <- as.numeric(cf)
  a <- (1 - level)/2
  a <- c(a, 1 - a)
  fac <- qt(a, object$df.residual)
  pct <- stats:::format.perc(a, 3)
  ses <- sqrt(diag(vcov(object)))
  ci <- ncfs + ses %o% fac
  setNames(data.frame(ci),pct)
}

Test:

fit_mlm <- lm(cbind(mpg, disp) ~ wt, mtcars)
confint(fit_mlm)

Gives:

                       2.5 %     97.5 %
mpg:(Intercept)    33.450500  41.119753
mpg:wt             -6.486308  -4.202635
disp:(Intercept) -204.091436 -58.205395
disp:wt            90.757897 134.198380

Personnally, I like it in a clean tibble way (using broom::tidy would be even better, but has an issue currently)

library(tidyverse)
confint(fit_mlm) %>% 
  rownames_to_column() %>% 
  separate(rowname, c("response", "term"), sep=":")

Gives:

  response        term       2.5 %     97.5 %
1      mpg (Intercept)   33.450500  41.119753
2      mpg          wt   -6.486308  -4.202635
3     disp (Intercept) -204.091436 -58.205395
4     disp          wt   90.757897 134.198380