[英]Edit fields inside a file using awk
I am trying to modify the second field of a list of data using awk 我正在尝试使用awk修改数据列表的第二个字段
Input : 输入:
8 : /usr/local/lib/python2.7/test/test_cookie.py : Image
Output: 输出:
8 : /usr/local/lib/python2.7/test/ : Image
I wanted to remove the file name from the second field using awk or sed. 我想使用awk或sed从第二个字段中删除文件名。
I already tried using awk command inside another awk to replace the second field of the input file. 我已经尝试在另一个awk中使用awk命令来替换输入文件的第二个字段。 However this is giving me error :
但是,这给了我错误:
cat log.txt |awk -F: '{$2=system(cat log.txt |awk -F":" '{print $2}'|awk -F/ '{OFS="/";$NF=""}{print $0}' )}{print $0}'
Can you help me with a more probable way to do the same. 您能以一种更可能的方式帮助我吗?
You can use this awk
: 您可以使用以下
awk
:
awk 'BEGIN{FS=OFS=" : "} {sub(/[^\/]+$/, "", $2)} 1' log.txt
8 : /usr/local/lib/python2.7/test/ : Image
Explanation: 说明:
BEGIN{FS=OFS=" : "} # Set input and output field separator as " : "
sub(/[^\/]+$/, "", $2) # Remove part after *last* / from 2nd field
1 # default awk action to print the record
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