计算两种数据类型之间MYSQL中的字段数

Question

OK weird question.

Table consists of multiple fields. Some with data type int(5) and the rest with datatype int(11)

So lets take a row...

id =>int(5)
var1 =>int(11)
var2 =>int(11)
var3 =>int(11)
var4 =>int(11)
var5 =>int(5)
var6 =>int(11)
var7 =>int(11)
var8 =>int(11)

How can I count the fields in PHP BETWEEN id (int(5)) and var (int(5)) I need to return the values in the fields between using php... but Im stuck. Bad table design doesnt help...but Im stuck with it.

The full scenario is that i need to create an if statement which says, output the name and and data of the int(5) field IF any of the fields between it and the next int(5) contain data

sorry... ugly I know!!!

If run this so far

    $sql2 = 'SHOW COLUMNS from services2';
    $result2 = getDBResults($sql2, $level, $testing);

    $total = count($result2);


    $i=2;
    while ($i<($total-1))
    {
        $data = $result2[$i]['Field'];

        if ($result2[$i][1]=='int(5)')
        {
            $html .= '<h2>'.preg_replace('/(?<!\ )[A-Z]/', ' $0', $result2[$i]['Field']).'</h2>';
        }
        else
        {   
            ];
            // "$result - This is a seperate query run previously to get the row
            if ($result[0][$data] == 1)
            {
                $html .= '<p>'.preg_replace('/(?<!\ )[A-Z]/', ' $0', $data).'</p>';
            }
        }
        $i++;
    }

Answer 1

I have not had a chance to actually test this, so dont beat me up if you need to tweek it a bit to smooth off any rough edges.

But its a fairly standard, if not totally simple, process of processing over the column names result array in a loop and just remembering the last int(5) column name in a variable so you can use it, if and only if, you have found some data in any int(11) column types before seeing the next int(5) column type.

Now I understand why you had trouble explaining what you wanted, I am having the same trouble describing a solution.

Anyway, have a look at this code and see if it makes any sence to you.

$sql2 = 'SHOW COLUMNS from services2';
$columns = getDBResults($sql2, $level, $testing);

$total = count($columns);

$print_column = null;
$found_data = false;

foreach ( $columns as $idx => $column ) {
    // skip first 2 columns
    if ($idx < 3 ) { continue; }

    // first time thru loop so remember the first int5 column name we saw
    if ( $column['Type'] == 'int(5)' && empty($print_column) ) {
        $print_column = $column['Field'];
        $found_data   = false;
        continue;
    }

    // found the next int5 column, do we need to print anything
    if ( $column['Type'] == 'int(5)' && $found_data ) {

        // This is where you would do any output creation, 
        // I just kept it simple.
        echo $result[0][$print_column];

        // reset state and the next field that might be printed.
        $found_data = false;
        $print_column = $column['Field'];
        continue;
    }

    // This may not need to be an if, but just in case you have other field types
    // that you are not interested in processing I made it an if.
    if ( $column['Type'] == 'int(11)' && ! empty($result[0][$column['Field']]) ) {
        $found_data = true;
    }

} // endforeach