如何同时执行两个Shell函数？

Question

I have written a shell script with functions which output some ASCII animation. I would like to execute two of these functions at the same time but have them display the art one under the other, for example:

function_one(){
clear
printf %s '
______________
||__________||

'
sleep 1
tput home
printf %s '
______________
||__________||
      ||
      ||
      ||

'
sleep 1
tput home
printf %s '
______________
||__________||
      ||
      ||
      ||
||‾‾‾‾‾‾‾‾‾‾||
‾‾‾‾‾‾‾‾‾‾‾‾‾‾
'
}

imagine this function continues to print more ASCII letters but in the same set of 7 lines it has already taken then underneath this I want another function to start:

function_two(){
sleep 10
printf %b "this is an example\r"
printf %b "this is more example\r"
printf %b "and some more\r"
}

function_two sleeps for a while to allow function_one to take all the space it needs but starts before function_one has finished and displays its output below function_one. Is this possible? I have tried piping the functions, eg:

function_one | function_two

but this only seems to execute function_two. Sorry, this isn't the easiest thing to explain but I hope you can understand. Thank you.

Answer 1

Advanced control of where on a display to print isn't something you can do trivially. You need to specify where to draw/etc.

Pipes send the output from one command to another command (so function_two there gets on its standard input the output from function_one which isn't at all what you want).

If you just don't want function_two to wait for function_one to finish put function_one in the background with & .

function_one &
function_two

But if function_one isn't done printing this isn't going to work how you want it to.