如何链接一系列返回promises的函数，并需要不同的参数？

Question

I have two asynchronous functions, which use parameters already acquired somehow:

var a = getUserinput();
var b = getUserinput();
var c = getUserinput();
var d = getUserinput();


var func1 = function(valA, valB){
     var deferred = $q.deferred;
     //http call with valA, valb...
     // when complete, resolve deferred
     return deferred.promise;
}

var func2 = function(valC, valD){
     var deferred = $q.deferred;
     //http call with valC, valD...
     // when complete, resolve deferred
     return deferred.promise;
}

I want to execute func1 and then func2 . The problem is that I can't find a way to do this successfully while being able to provide parameters to func2 .

For example, if I do

func1(a, b).then(func2(c, d));

func2 executes before func1 is done.

How do I execute func2 only after func1 is done?

func

Answer 1

Provide anonymous function and place func2 invocation in it:

func1(a, b).then(function() {
    func2(c, d);
});

Answer 2

If it helps, I recently took the first release of the rogue written for UNIX in C and rewrote it for javascript to work in a browser. I used a technic called continuation to be able to wait for key entry by the user because in javascript the are no interrupts.

So I would have a piece of code like this:

void function f() {

  // ... first part

  ch = getchar();

  // ... second part

}

that would be transformed in

function f() {

  // ... first part

  var ch = getchar(f_cont1);

  return;
  // the execution stops here 

  function f_cont1 () {

    // ... second part
  }
}

the continuation is then stored to be reuse on a keypressed event. With closures everything would be restarted where it stoped.