[英]How to chain functions returning promises or values?
I have an array of functions which I want to execute in order, some of those functions return a promise, while others simply return a value. 我有一个要按顺序执行的函数数组,其中一些函数返回promise,而其他一些则仅返回值。
I want the functions to be executed one at a time, in order they appear in the array. 我希望函数一次执行一次,以便它们出现在数组中。 If the function returns a promise, I want to wait until it resolves to a value. 如果函数返回一个Promise,我要等到它解析为一个值。 If it returns a value, I want it to simply use that value. 如果它返回一个值,我希望它简单地使用该值。
Example of how I want it to work: 我希望它如何工作的示例:
function f1() {
return 1;
}
function f2() {
return new Promise(function (resolve, reject) {
// ...
resolve(4);
}).then(function (num) {return num / 2; });
}
function f3() {
return Promise.resolve("3");
}
var array = [f1, f2, f3];
chain(array).then(function (values) {
// values == [1, 2, "3"];
});
In case any of the promises fail, the chain function should stop execution and pass the error further. 万一任何承诺失败,链函数应停止执行并进一步传递错误。
Your current solution is pretty overkill, promises already accept values and/or promises with .then
, you can refactor your code to this: 您当前的解决方案是过大的,promise已经接受了值和/或使用.then
promise,您可以将代码重构为:
var queue = Promise.resolve(); // start empty queue
var results = arr.map(function(el){
return (queue = queue.then(function(){ // update the queue to wait for next promise
return el(); // call the function, return it so the array resolves to it
}));
});
Promise.all(results).then(function(results){
// access all results here
});
Figured this out while making the question and decided to share. 在提出问题时想出了这一点,并决定分享。
function chain(array) {
array = array.slice(); // Make a copy
var result = [];
return new Promise(function (resolve, reject) {
(function chainLoop() { // Make an IIFE-based loop
if (array.length > 0) { // If we have elements in the array...
Promise.resolve(array.shift()()) // Remove and resolve value of first element from the array
.then(function (value) {
result.push(value); // Push onto the result
chainLoop(); // Loop - This won't cause a stack overflow, promises reset the stack
}, reject);
} else { // Otherwise, if the array is empty...
resolve(result); // resolve with our result array.
}
}());
});
}
Usage: 用法:
chain([f1, f2, f3]).then(function (values) {
console.log(values); // [1, 2, "3"] (assuming f1, f2, f3 from the question)
});
This will crash if there are non-functions in the array, so there is room for improvement, but this fits my needs so far. 如果阵列中没有功能,这将导致崩溃,因此仍有改进的空间,但这到目前为止满足了我的需求。
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