查询生成器-带有子查询的whereRaw

Question

I need to create the following query using Laravel Query Builder:

SELECT count(*) FROM table WHERE 1 < (SELECT count(*) FROM x WHERE y=2)

the question is - is it possible to do it using query builder?

The only why I was able to achieve it is:

\DB::table('table')->whereRaw('1 < (SELECT count(*) FROM x WHERE y=2)')->count();

but this way I need to manually put here subquery and it's generating wrong query:

SELECT count(*) FROM table WHERE 1 < (SELECT count(*) FROM x WHERE y=2) IS NULL

( is null is added at the end)

Is it possible to use here query builder also for subquery and make it to generate correct SQL?

Answer 1

The only solution I found is creating separate query builder this way:

$subQuery = \DB::table('x')->selectRaw('count(*)')->where('y',2);

\DB::table('table')->whereRaw('1 < ('.$subQuery->toSql().')')->addBinding($subQuery->getBindings());

Answer 2

尝试这个

\DB::table('table')->where(DB::raw('SELECT count(*) FROM x WHERE y=2'), '<',1)->count();