[英]Convert indexed DataFrame to multi-indexed using pattern in indices
I have the DataFrame with the following structure (ie indices has some lexical intersections): 我的DataFrame具有以下结构(即索引具有一些词法交集):
a b
bar foo bah foo
A1B1 1 0 3 2
A1B2 5 4 7 6
A2B1 9 8 11 10
A2B2 13 12 15 14
I want this DataFrame to be converted into this (ie multi-index from index using some regular expression): 我希望将此DataFrame转换为此(即使用某些正则表达式从索引中创建多索引):
a b
bar foo bah foo
A1 B1 1 0 3 2
B2 5 4 7 6
A2 B1 9 8 11 10
B2 13 12 15 14
I would probably just use map: 我可能只会使用map:
In [11]: df.index = pd.MultiIndex.from_tuples(df.index.map(lambda x: (x[0:2], x[2:4])))
In [12]: df
Out[12]:
a b
bar foo bah foo
A1 B1 1 0 3 2
B2 5 4 7 6
A2 B1 9 8 11 10
B2 13 12 15 14
You can use regex, or whatever, provided the function you pass to map takes each item and returns a tuple. 您可以使用正则表达式或任何其他形式,只要传递给map的函数接受每个项目并返回一个元组即可。
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