简体   繁体   English

如何在select * from中动态选择 <table_name> 分区(分区名称)?

[英]how to select dynamically in select * from <table_name> partiton (Partition name)?

i have a big table with several partition. 我有几个分区的大桌子。 my partition name is like below: 我的分区名称如下所示:

P_13931203
P_13931204
P_13931205
P_13931206

i have a select for create partition name dynamically as below: 我可以选择动态创建分区名称,如下所示:

select 'P_' || to_char(sysdate-1,'yyyymmdd','nls_calendar=persian') from dual;
example Output: P_13931204

when i select as below everything is OK: 当我选择如下时,一切都很好:

select *
from <table_name> partition (P_13931205);

but when i select as below i get error: 但是当我如下选择时,我得到错误:

select *
from <table_name> partition (select 'P_' || to_char(sysdate-1,'yyyymmdd','nls_calendar=persian') from dual);

error: 错误:

ORA-00933: SQL command not properly ended 00933. 00000 - "SQL command not properly ended" *Cause: ORA-00933:SQL命令未正确终止00933。00000-“ SQL命令未正确终止” *原因:
*Action: Error at Line: 2 Column: 28 syntax error, expected : identifier *操作:第2行错误:第28列语法错误,预期为:标识符

Try this:- 尝试这个:-

select * from partition 
(select 'P_' || to_char( sysdate-1,'yyyymmdd','nls_calendar=persian') from dual
) Dummy_table;

Beacuse after every sub-query select you have to mention a dataset name. 因为在选择每个子查询之后,您都必须提及数据集名称。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM