等待任何任务完成，然后开始一个新任务

Question

I'm wondering how could I, without doing my own implementation of reporting using blocking queues and similar, as easily as possible implement the following scenario:

I have K * N tasks, every batch of N tasks is a bit different.

1. Submit the first batch of N tasks (the work is done concurrently on every task)
2. When any of the tasks finishes submit a new one (taking it from the second batch)

The second point is repeated until all of the tasks are finished.

Should I use a CyclicBarrier and submit a task when there's one thread waiting? I guess I'd have to use a blocking queue to guarantee that I won't submit the same task twice.

Answer 1

如果要确保第一批不与第三批混合（等等），则可以为每批中使用批处理中的任务数初始化的CountDownLatch，并且批处理中的任务应等待（）在对应于批次N-2的锁存器上，并且当任务完成时，它可以在其相应的锁存器上调用countDown（）。