用php替换动态链接

Question

I wan to replace dynamic links in text with text like:
if the links are

<a href="show.php?id=3">Number three</a>
<a href="show.php?id=4">Number four</a>
<a href="show.php?id=1">StackOverflow</a>
<a href="view.php?id=9">Foo</a>

I want this returned

Number three
Number four
StackOverflow
<a href="view.php?id=9">Foo</a>

What will be the perfect regex for this, I tried handful of regex but they just don't work.
EDIT:

String contains other links like view.php?id=5 and I don't want to replace them.

Answer 1

This should work:

$regex = '~<a href="show.php\?id=\d+">([^<]*)</a>~Ui';
$output = preg_replace($regex, '$1', $input);

Answer 2

$html = '
    <a href="show.php?id=3">Number three</a>
    <a href="show.php?id=4">Number four</a>
    <a href="show.php?id=1">StackOverflow</a>
    <a href="view.php?id=9">Foo</a>
';

$doc = new DOMDocument();
$doc->loadHTML($html);

foreach ($doc->getElementsByTagName("a") as $a) {
    if (strpos($a->getAttribute("href"), "show.php") === 0) {
        echo $a->nodeValue . "\n";
    } else {
        echo $doc->saveHTML($a) . "\n";
    }
}

will output:

Number three
Number four
StackOverflow
<a href="view.php?id=9">Foo</a>

Answer 3

You need to use a negative lookahead based regex.

<a href="(?!view\.php\?id=\d+")[^"]*">([^<>]*)</a>

DEMO

$re = "~<a href=\"(?!view\\.php\\?id=\\d+\")[^\"]*\">([^<>]*)</a>~m";
$str = "<a href=\"show.php?id=3\">Number three</a>\n<a href=\"show.php?id=4\">Number four</a>\n<a href=\"show.php?id=1\">StackOverflow</a>\n<a href=\"view.php?id=9\">Foo</a>";
$subst = "$1";

$result = preg_replace($re, $subst, $str);