PHP替换链接

Question

I have been racking my brains over this for hours, I need to pass some html to a function and have it replace the links and the return the html with the replaced links. 我已经花了好几个小时思考一下，我需要将一些html传递给函数，并让它替换链接，并用替换的链接返回html。

<?php
    final static public function replace_links($campaign_id, $text) {
        $regexp = "<a\s[^>]*href=(\"??)([^\" >]*?)\\1[^>]*>(.*)<\/a>";
        if(preg_match_all("/$regexp/siU", $text, $matches, PREG_SET_ORDER)) {
            foreach($matches as $match) {
                if(substr($match[2], 0, 2) !== '##') {  //  ignore the placeholders
                    if(substr($match[2], 0, 6) !== 'mailto') {  //  ignore email addresses
                        // $match[2] = link address
                        // $match[3] = link text
                        $url = "http://xxx.com/click?campaign_id=$campaign_id&email=##email_address##&next=" . $match[2];
                        #$text .= str_replace($match[2], $url, $text);
                        #echo $links . "\n";
                        preg_replace($match[2], "<a href='$url'>{$match[3]}</a>", $match[2]);
                    }
                }
                return $text;
            }
        }
    }
?>

When I echo the links it shows all the matched links. 当我回显链接时，它会显示所有匹配的链接。 Question is how do i return the complete HTML with the replaced links example below. 问题是如何返回下面带有替换链接示例的完整HTML。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<a href="mailto:sssss">xxxx</a>
<a href="http://www.abc.com/">xxxx</a>
<a href="http://www.google.com/yeah-baby-yeah">xxxx</a>
</body>
</html>

Should become: 应该变成：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<a href="mailto:sssss">xxxx</a>
<a href="https://xxx.com/click?next=http://www.abc.com/">xxxx</a>
<a href="https://xxx.com/click?next=http://www.google.com/yeah-baby-yeah">xxxx</a>
</body>
</html>

Hope this makes sense. 希望这是有道理的。

Thanks in advance, 提前致谢，

Kyle 凯尔

Answer 1

Don't reinvent the wheel just use something like this: 不要重新发明轮子，只需使用如下所示的内容：

http://code.google.com/p/jquery-linkify/ http://code.google.com/p/jquery-linkify/

It's really easy i use it as well 我也很容易使用它

Answer 2

I don't know much about preg_replace, but i needed exatcly the same function as you. 我对preg_replace不太了解，但是我需要与您完全相同的功能。 Changing the line: 换行：

preg_replace($match[2], "<a href='$url'>{$match[3]}</a>", $match[2]);

for this: 为了这：

str_replace($match[0],$url,$text);

seems to do the trick. 似乎可以解决问题。

I just needed to get the return from this functions, so: 我只需要从此函数中获得收益，所以：

//$text = preg_replace($match[2], "<a href='$url'>{$match[3]}</a>", $match[2]);
$text = str_replace($match[0],$url,$text);

PHP替换链接

问题描述

2 个解决方案

解决方案1
0 2012-04-03 19:42:26

解决方案2
0 2012-08-15 15:40:17

PHP替换链接

问题描述

2 个解决方案

解决方案1 0 2012-04-03 19:42:26

解决方案2 0 2012-08-15 15:40:17

解决方案1
0 2012-04-03 19:42:26

解决方案2
0 2012-08-15 15:40:17