使用 dplyr::filter() 删除 NA 观察

Question

My data looks like this:

library(tidyverse)

df <- tribble(
    ~a, ~b, ~c,
    1, 2, 3, 
    1, NA, 3, 
    NA, 2, 3
)

I can remove all NA observations with drop_na() :

df %>% drop_na()

Or remove all NA observations in a single column ( a for example):

df %>% drop_na(a)

Why can't I just use a regular != filter pipe?

df %>% filter(a != NA)

Why do we have to use a special function from tidyr to remove NAs?

Answer 1

For example:

you can use:

df %>% filter(!is.na(a))

to remove the NA in column a.

Answer 2

From @Ben Bolker:

[T]his has nothing specifically to do with dplyr::filter()

From @Marat Talipov:

[A]ny comparison with NA, including NA==NA, will return NA

From a related answer by @farnsy:

The == operator does not treat NA's as you would expect it to.

Think of NA as meaning "I don't know what's there". The correct answer to 3 > NA is obviously NA because we don't know if the missing value is larger than 3 or not. Well, it's the same for NA == NA. They are both missing values but the true values could be quite different, so the correct answer is "I don't know."

R doesn't know what you are doing in your analysis, so instead of potentially introducing bugs that would later end up being published an embarrassing you, it doesn't allow comparison operators to think NA is a value.

Answer 3

如果 2020 年有人在这里，在制作完所有管道后，如果 u pipe %>% na.exclude将带走管道中的所有 NA！

Answer 4

I always use this and it is working perfectly

cool$day[cool$day==''] <- NA
cool$day[is.na(cool$day)] <- "NA"

cool <- cool[!cool$day == "NA", ]