[英]in Java, how to create n number of Strings with certain properties
What I would like to do is produce n number of Strings and each string should have 2 char and 4 numbers randomly shuffled, for ex: 2w3e45 34rt56 qw5498 0126fd w5487t 我想做的是产生n个字符串,每个字符串应随机包含2个字符和4个数字,例如:2w3e45 34rt56 qw5498 0126fd w5487t
and so on, I have the following, it is working, any enhancements could be applied? 依此类推,我有以下内容,它正在起作用,可以应用任何增强功能吗? Also, can we have them as unique strings? 另外,我们可以将它们作为唯一的字符串吗?
import java.util.Random;
public class RandomNumAndChar {
public static void main(String[] args) {
for (int j = 0; j < 10; j++) {
Random r = new Random();
Integer[] rn = new Integer[4];
String numbers = new String();
for (int i = 0; i < rn.length; i++) {
rn[i] = r.nextInt(10);
numbers = numbers + rn[i].toString();
}
char c = (char) (r.nextInt(26) + 'a');
char c2 = (char) (r.nextInt(26) + 'a');
String chars = "" + c + c2;
String fin = numbers.concat(chars);
System.out.println(RandomNumAndChar.shuffle(fin));
}
}
public static String shuffle(String s) {
char[] characters = s.toCharArray();
for (int i = 0; i < characters.length; i++) {
int randomIndex = (int)(Math.random() * characters.length);
char temp = characters[i];
characters[i] = characters[randomIndex];
characters[randomIndex] = temp;
}
return new String(characters);
}
} }
As stated in the comments this is more suitable for CodeReview Stack Exchange . 如评论中所述,这更适合CodeReview Stack Exchange 。 However here are some guidelines I'll use to perform the task: 但是,以下是一些我将用来执行任务的准则:
Character
array to store the code. 使用6个Character
数组存储代码。 Beware I said Character
, not char
. 当心我说的是Character
,不是char
。 This is because Java is more flexible when dealing with wrappper classes. 这是因为Java在处理包装类时更加灵活。 Collections#shuffle()
to shuffle your array. 使用Collections#shuffle()
来随机排列数组。 Here is where Character
comes in hand, since we need to convert the array in a List
with Arrays#asList()
. 这是Character
出现的地方,因为我们需要使用Arrays#asList()
在List
转换数组。 Using this simple guidelines you get something like: 使用这个简单的准则,您将得到类似:
class Test {
static Random r = new Random();
public static void main(String[] a) {
for (int i = 0; i < 10; i++) {
System.out.println(getNewCode());
}
}
private static String getNewCode() {
Character[] array = new Character[6];
int i = 0;
while(i < 4) array[i++] = (char) ('0' + r.nextInt(10));
array[4] = (char) ('a' + r.nextInt(26));
array[5] = (char) ('a' + r.nextInt(26));
List<Character> l = Arrays.asList(array);
Collections.shuffle(l);
StringBuilder sb = new StringBuilder();
for (char s : l)
sb.append(s);
return sb.toString();
}
}
Sample output: 样本输出:
e1v456
8s632b
t7810w
n9801y
76q14c
p2a881
27m7k1
1081st
m19u36
t03h77
More conviniently you could start directly using a List
instead of an array: 更方便的是,您可以直接使用List
而不是数组:
class Test {
static Random r = new Random();
public static void main(String[] a) {
for (int i = 0; i < 10; i++) {
System.out.println(getNewCode());
}
}
private static String getNewCode() {
List<Character> l = new ArrayList<Character>();
int i = 0;
for(int i = 0; i<4; i++)
l.add((char) ('0' + r.nextInt(10)));
l.add((char) ('a' + r.nextInt(26)));
l.add((char) ('a' + r.nextInt(26)));
Collections.shuffle(l);
StringBuilder sb = new StringBuilder();
for (char s : l)
sb.append(s);
return sb.toString();
}
}
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