[英]How can i create a recursive method that does the exp of n but returns a String n number of times in Java
[英]in Java, how to create n number of Strings with certain properties
我想做的是產生n個字符串,每個字符串應隨機包含2個字符和4個數字,例如:2w3e45 34rt56 qw5498 0126fd w5487t
依此類推,我有以下內容,它正在起作用,可以應用任何增強功能嗎? 另外,我們可以將它們作為唯一的字符串嗎?
import java.util.Random;
public class RandomNumAndChar {
public static void main(String[] args) {
for (int j = 0; j < 10; j++) {
Random r = new Random();
Integer[] rn = new Integer[4];
String numbers = new String();
for (int i = 0; i < rn.length; i++) {
rn[i] = r.nextInt(10);
numbers = numbers + rn[i].toString();
}
char c = (char) (r.nextInt(26) + 'a');
char c2 = (char) (r.nextInt(26) + 'a');
String chars = "" + c + c2;
String fin = numbers.concat(chars);
System.out.println(RandomNumAndChar.shuffle(fin));
}
}
public static String shuffle(String s) {
char[] characters = s.toCharArray();
for (int i = 0; i < characters.length; i++) {
int randomIndex = (int)(Math.random() * characters.length);
char temp = characters[i];
characters[i] = characters[randomIndex];
characters[randomIndex] = temp;
}
return new String(characters);
}
}
如評論中所述,這更適合CodeReview Stack Exchange 。 但是,以下是一些我將用來執行任務的准則:
Character
數組存儲代碼。 當心我說的是Character
,不是char
。 這是因為Java在處理包裝類時更加靈活。 Collections#shuffle()
來隨機排列數組。 這是Character
出現的地方,因為我們需要使用Arrays#asList()
在List
轉換數組。 使用這個簡單的准則,您將得到類似:
class Test {
static Random r = new Random();
public static void main(String[] a) {
for (int i = 0; i < 10; i++) {
System.out.println(getNewCode());
}
}
private static String getNewCode() {
Character[] array = new Character[6];
int i = 0;
while(i < 4) array[i++] = (char) ('0' + r.nextInt(10));
array[4] = (char) ('a' + r.nextInt(26));
array[5] = (char) ('a' + r.nextInt(26));
List<Character> l = Arrays.asList(array);
Collections.shuffle(l);
StringBuilder sb = new StringBuilder();
for (char s : l)
sb.append(s);
return sb.toString();
}
}
樣本輸出:
e1v456
8s632b
t7810w
n9801y
76q14c
p2a881
27m7k1
1081st
m19u36
t03h77
更方便的是,您可以直接使用List
而不是數組:
class Test {
static Random r = new Random();
public static void main(String[] a) {
for (int i = 0; i < 10; i++) {
System.out.println(getNewCode());
}
}
private static String getNewCode() {
List<Character> l = new ArrayList<Character>();
int i = 0;
for(int i = 0; i<4; i++)
l.add((char) ('0' + r.nextInt(10)));
l.add((char) ('a' + r.nextInt(26)));
l.add((char) ('a' + r.nextInt(26)));
Collections.shuffle(l);
StringBuilder sb = new StringBuilder();
for (char s : l)
sb.append(s);
return sb.toString();
}
}
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