如何在python中转换此数据结构

Question

I have the following Python structure.

{'2015-03-03': 
    [{'traffic': 80.0, 'Server': 'Server1'},
     {'traffic': 20.0, 'Server': 'Server2'}],
 '2015-03-04':
    [{'traffic': 100.0, 'Server': 'Server1'}]}

I need to convert this to a dictionary as

{"Series": 
    [{'traffic': [80.0, 20.0], 'Server': 'Server1'},
     {'traffic’: [100.0, 0], ’Server': 'Server2'}],
 "dates" : 
    [“2015-03-03”, 2015-03-04”]}

I tried the following. (result had the first dictionary)

final_data = {}
final_data['series'] = []
final_data['dates'] = sorted(result.keys())
for key in final_data['dates']:
    final_data['series'].append(result[key])

But this does not yield the converted data structure. Any help?

Answer 1

What about:

di = {
    '2015-03-03': [{'traffic': 80.0, 'Server': 'Server1'},
                   {'traffic': 20.0, 'Server': 'Server2'}],
    '2015-03-04': [{'traffic': 100.0, 'Server': 'Server1'}]
}


dates = sorted(di.keys())                                       # Get all dates
servers = set(e['Server'] for v in di.values() for e in v)      # Get all servers

# Refactor the dictionary
df = {}
for (k,v) in di.iteritems():
    df[k] = {}
    for elem in v:
        df[k][elem['Server']] = elem['traffic']

# Compute series (if the [date][server] key-chain doesn't exist in df, use 0)
series = []
for server in servers:
    traffic = []
    for date in dates:
        try:    traffic.append(df[date][server])
        except: traffic.append(0)
    series.append({'traffic':traffic, 'Server':server})

# Create output dict
do = {
    'Series': series,
    'dates': dates,
}

print do

Output:

{
    'Series': [
        {'traffic': [80.0, 100.0], 'Server': 'Server1'}, 
        {'traffic': [20.0, 0], 'Server': 'Server2'}
    ], 
    'dates': ['2015-03-03', '2015-03-04']
}

Note that this differs from your expected output . In your expected output you had do['Series'][0]['traffic'] = [80.0, 20.0] but I have [80.0, 100.0] -- since they're the traffic entries corresponding to 'Server1'.

If you really want [80.0, 20.0] , I'm going to need to know what logic you're using to make that connection.