[英]How to convert this data structure in python
我有以下Python結構。
{'2015-03-03':
[{'traffic': 80.0, 'Server': 'Server1'},
{'traffic': 20.0, 'Server': 'Server2'}],
'2015-03-04':
[{'traffic': 100.0, 'Server': 'Server1'}]}
我需要將其轉換為字典
{"Series":
[{'traffic': [80.0, 20.0], 'Server': 'Server1'},
{'traffic’: [100.0, 0], ’Server': 'Server2'}],
"dates" :
[“2015-03-03”, 2015-03-04”]}
我嘗試了以下方法。 (結果有第一本字典)
final_data = {}
final_data['series'] = []
final_data['dates'] = sorted(result.keys())
for key in final_data['dates']:
final_data['series'].append(result[key])
但這不會產生轉換后的數據結構。 有什么幫助嗎?
關於什么:
di = {
'2015-03-03': [{'traffic': 80.0, 'Server': 'Server1'},
{'traffic': 20.0, 'Server': 'Server2'}],
'2015-03-04': [{'traffic': 100.0, 'Server': 'Server1'}]
}
dates = sorted(di.keys()) # Get all dates
servers = set(e['Server'] for v in di.values() for e in v) # Get all servers
# Refactor the dictionary
df = {}
for (k,v) in di.iteritems():
df[k] = {}
for elem in v:
df[k][elem['Server']] = elem['traffic']
# Compute series (if the [date][server] key-chain doesn't exist in df, use 0)
series = []
for server in servers:
traffic = []
for date in dates:
try: traffic.append(df[date][server])
except: traffic.append(0)
series.append({'traffic':traffic, 'Server':server})
# Create output dict
do = {
'Series': series,
'dates': dates,
}
print do
輸出:
{
'Series': [
{'traffic': [80.0, 100.0], 'Server': 'Server1'},
{'traffic': [20.0, 0], 'Server': 'Server2'}
],
'dates': ['2015-03-03', '2015-03-04']
}
請注意, 這與您的預期輸出不同 。 在您的預期輸出中,您有do['Series'][0]['traffic'] = [80.0, 20.0]
但我有[80.0, 100.0]
-因為它們是與“ Server1”相對應的流量條目。
如果您確實想要[80.0, 20.0]
,那么我將需要知道您用於建立該連接的邏輯。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.