两个数组与三个for循环的比较

Question

My title isn't the best but i haven't any other ideas. I have one List of objects with a List categories parameter and one String . The String is something like: "action,azione adventure,avventura horror sport " . I have to split it with spaces to obtain an array of strings like: ["action,azione", "adventure,avventura", "horror", "sport"] . I have to remove an item from the List of objects if his List categories item isn't contained in the array of String. I know that it could sound tricky so i'll make some example:

Array: ["action,azione", "adventure,avventura", "horror", "sport"]

List categories (of the actual List object): ["action", "adventure", "horror", "comic", "sport"] remain

Array: ["action,azione", "adventure,avventura", "horror", "sport"]

List categories (of the actual List object): ["azione", "horror", "comico", "sport"] delete because adventure categories isn't there

Here is my try:

listaManga.getManga() is the List of objects

listaManga.getManga().get(index).getC() is the List of categories of that object

String[] categories is the String splitted in spaces

String[] categories = MainActivity.categories.split(" ");

    for (int i = 0; i < listaManga.getManga().size(); i++) {
        for (int j = 0; j < categories.length; j++) {
            for (int z = 0; z < listaManga.getManga().get(i).getC().size(); z++) {
                if (!categories[j].contains(String.valueOf(listaManga.getManga().get(i).getC().get(z)))) {
                      listaManga.getManga().remove(i);
                      break;
                }
            }
        }
   }

It throws IndexOutOfBoundsException on j value.

Answer 1

See if the following works.

String[] categories = MainActivity.categories.split(" ");
boolean found = false;
for (int i = (listaManga.getManga().size() - 1); i >= 0; i--) {
    found = false;
    for (int j = (categories.length - 1); j >= 0; j--) {
        for (int z = (listaManga.getManga().get(i).getC().size() - 1); z >= 0; z--) {
            if (!categories[j].contains(String.valueOf(listaManga.getManga().get(i).getC().get(z)))) {
                  listaManga.getManga().remove(i);
                  // Either do this
                  // i = i - 1;
                  // or put a flag here that is
                  // found == true;

                  break;
            }

            //if(found == true){
            //     break;
            //}
        }
    }
   }

Answer 2

I finally solved it following the inverse loop cycle idea but i had to change the code of muasif80 cause his code take to an issue: It can get right categories only if in listaManga.getManga().get(i).getC() there aren't more categories. I'll make an example: if i have ["comic", "adventure"] as String[] categories , it will find all list item with ["comic", "adventure"] categories but not also item with more other categories like: ["comic", "adventure", "horror"] .

I did it setting a new String to check every possibility:

String is_contained = "";
String[] categories = MainActivity.categories.split(" ");
for (int i = (listaManga.getManga().size() - 1); i >= 0; i--) {
    if(listaManga.getManga().get(i).getC().size()==0){
         listaManga.getManga().remove(i);
    } else {
         for (int j = (categories.length - 1); j >= 0; j--) {
            is_contained = "";
            for (int z = (listaManga.getManga().get(i).getC().size() - 1); z >= 0; z--) {
                if (!categories[j].toLowerCase().contains((String.valueOf(listaManga.getManga().get(i).getC().get(z))).toLowerCase())) {
                      is_contained += "a";
                } else {
                      is_contained += "b";
                }
            }
            if (!is_contained.toLowerCase().contains(("b").toLowerCase())) {
                listaManga.getManga().remove(i);
                break;
            }
        }
    }
}

Ps Also if this is the most correct answer, i'll accept the one of muasif80 for all the time that he dedicated to me in chat!