[英]Get the name of the function from inside the function
Is it possible to get the name of the function from inside the function? 是否可以从函数内部获取函数名称?
Example: 例:
function myFunction() {
// console.log the name of this function without knowing/specifying what the name is
// otherwise console.log('myFunction was called'); is
// more obvious (and better supported) than console.log(myFunction.name);
// console.log(arguments.callee.name); works but not in strict mode and is deprecated
}
Reference: 参考:
Function.name Function.name
arguments.callee arguments.callee的
Update: 更新:
From the comments and answers, it appears that the point has been completely missed. 从评论和答案看来,这一点已被完全遗漏了。
I revised the example to make it clearer. 我修改了示例以使其更加清晰。
Update 2: 更新2:
It seems there is still ambiguity ... here is an example of a debugging process: 似乎仍然有歧义...这是调试过程的示例:
function one() {
console.log(arguments.callee.name + ' was called'); // one was called
// reset of the code
}
function two() {
console.log(arguments.callee.name + ' was called'); // two was called
// reset of the code
}
function three() {
console.log(arguments.callee.name + ' was called'); // three was called
// reset of the code
}
function four() {
console.log(arguments.callee.name + ' was called'); // four was called
// reset of the code
}
function five() {
console.log(arguments.callee.name + ' was called'); // five was called
// reset of the code
}
arguments.callee.name
is deprecated and not available in strict mode. arguments.callee.name
已弃用,在严格模式下不可用。
I am looking for a method that is not deprecated and works in strict mode. 我正在寻找一种不建议弃用且在严格模式下有效的方法。
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