从函数内部获取函数名称

Question

是否可以从函数内部获取函数名称？
例：

function myFunction() {

  // console.log the name of this function without knowing/specifying what the name is
  // otherwise console.log('myFunction was called'); is 
  // more obvious (and better supported) than console.log(myFunction.name);
  // console.log(arguments.callee.name); works but not in strict mode and is deprecated
}

参考：
Function.name
arguments.callee的

更新：
从评论和答案看来，这一点已被完全遗漏了。
我修改了示例以使其更加清晰。

更新2：
似乎仍然有歧义...这是调试过程的示例：

function one() {
  console.log(arguments.callee.name + ' was called'); // one was called
  // reset of the code
}

function two() {
  console.log(arguments.callee.name + ' was called'); // two was called
  // reset of the code
}

function three() {
  console.log(arguments.callee.name + ' was called'); // three was called
  // reset of the code
}

function four() {
  console.log(arguments.callee.name + ' was called'); // four was called
  // reset of the code
}

function five() {
  console.log(arguments.callee.name + ' was called'); // five was called
  // reset of the code
}

arguments.callee.name已弃用，在严格模式下不可用。
我正在寻找一种不建议弃用且在严格模式下有效的方法。

Answer 1

尝试这个...

console.log(myFunction.name);

请注意，这不是由IE还提到支持这里