Spring JMS无法连接到WebSphere MQ-身份验证失败

Question

I config the WebSphere MQ with following command:

DEFINE QLOCAL(NEW.QL.RQ)
DEFINE QLOCAL(NEW.QL.RS)
DEFINE LISTENER('NEW.LSR') TRPTYPE(TCP) PORT(1420) CONTROL(QMGR) 
START LISTENER('NEW.LSR')
DEFINE CHANNEL('NEW.SVR.CONN') CHLTYPE(SVRCONN)
SET CHLAUTH(*) TYPE(BLOCKUSER) USERLIST('nobody','*MQADMIN')
SET CHLAUTH(SYSTEM.ADMIN.*) TYPE(BLOCKUSER) USERLIST('nobody')
SET CHLAUTH(NEW.SVR.CONN) TYPE(ADDRESSMAP) ADDRESS(*) USERSRC(CHANNEL)
SET CHLAUTH(NEW.SVR.CONN) TYPE(BLOCKUSER) USERLIST('nobody')
REFRESH SECURITY

Then I can use MQ Explore connect to it successfully be using mqm username and empty password.

However, when I use spring jms, the authentication fail. The following section is my xml config.

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
                           http://www.springframework.org/schema/beans/spring-beans.xsd
                           http://www.springframework.org/schema/context 
                           http://www.springframework.org/schema/context/spring-context.xsd">

    <context:property-placeholder location="classpath:main.properties" />

    <!-- WebSphere MQ Connection Factory -->
    <bean id="mqConnectionFactory" class="com.ibm.mq.jms.MQQueueConnectionFactory">
        <property name="hostName">
            <value>${queue_hostname}</value>
        </property>
        <property name="port">
            <value>${queue_port}</value>
        </property>
        <property name="queueManager">
            <value>${queue_manager}</value>
        </property>
        <property name="transportType">
            <value>1</value>
        </property>
    </bean>

    <bean id="jmsConnectionFactory"
        class="org.springframework.jms.connection.UserCredentialsConnectionFactoryAdapter">
        <property name="targetConnectionFactory" ref="mqConnectionFactory" />
        <property name="username">
            <value>${mq.username}</value>
        </property>
        <property name="password">
            <value>${mq.password}</value>
        </property>
    </bean>

    <!-- JMS Destination Resolver -->
    <bean id="jmsDestinationResolver"
        class="org.springframework.jms.support.destination.DynamicDestinationResolver">
    </bean>

    <!-- JMS Queue Template -->
    <bean id="jmsQueueTemplate" class="org.springframework.jms.core.JmsTemplate102">
        <property name="connectionFactory">
            <ref bean="jmsConnectionFactory" />
        </property>
        <property name="destinationResolver">
            <ref bean="jmsDestinationResolver" />
        </property>
        <property name="pubSubDomain">
            <value>false</value>
        </property>
        <property name="receiveTimeout">
            <value>20000</value>
        </property>
    </bean>

    <bean id="messageService" class="com.test.testspringjmsmq.MessageService" />
</beans>

The error messages:

Caused by: com.ibm.msg.client.jms.DetailedJMSSecurityException: JMSWMQ2013: The security authentication was not valid that was supplied for QueueManager 'LOROL' with connection mode 'Client' and host name 'xx.xx.xx.xx'. Please check if the supplied username and password are correct on the QueueManager you are connecting to
at com.ibm.msg.client.wmq.common.internal.Reason.reasonToException(Reason.java:531)
at com.ibm.msg.client.wmq.common.internal.Reason.createException(Reason.java:219)
at com.ibm.msg.client.wmq.internal.WMQConnection.<init>(WMQConnection.java:410)
at com.ibm.msg.client.wmq.factories.WMQConnectionFactory.createV7ProviderConnection(WMQConnectionFactory.java:7855)
at com.ibm.msg.client.wmq.factories.WMQConnectionFactory.createProviderConnection(WMQConnectionFactory.java:7331)
at com.ibm.msg.client.jms.admin.JmsConnectionFactoryImpl.createConnection(JmsConnectionFactoryImpl.java:276)
at com.ibm.mq.jms.MQConnectionFactory.createCommonConnection(MQConnectionFactory.java:6055)
at com.ibm.mq.jms.MQTopicConnectionFactory.createTopicConnection(MQTopicConnectionFactory.java:114)
at com.ibm.mq.jms.MQTopicConnectionFactory.createConnection(MQTopicConnectionFactory.java:197)
at org.springframework.jms.connection.SingleConnectionFactory.doCreateConnection(SingleConnectionFactory.java:343)
at org.springframework.jms.connection.SingleConnectionFactory.initConnection(SingleConnectionFactory.java:290)
at org.springframework.jms.connection.SingleConnectionFactory.createConnection(SingleConnectionFactory.java:227)
at org.springframework.jms.support.JmsAccessor.createConnection(JmsAccessor.java:184)
at org.springframework.jms.core.JmsTemplate.execute(JmsTemplate.java:461)
... 25 more
Caused by: com.ibm.mq.MQException: JMSCMQ0001: WebSphere MQ call failed with compcode '2' ('MQCC_FAILED') reason '2035' ('MQRC_NOT_AUTHORIZED').
at com.ibm.msg.client.wmq.common.internal.Reason.createException(Reason.java:206)
... 37 more

Answer 1

Finally, I do not use Spring JMS to implement the connection between java and WebSphere MQ.

I directly use the simple JMS to implement it, and I think the configuration is more easy than Spring JMS.

The following section is the sample code for simple jms.

try {
      MQQueueConnectionFactory cf = new MQQueueConnectionFactory();

      // Config
      cf.setHostName("localhost");
      cf.setPort(1414);
      cf.setTransportType(JMSC.MQJMS_TP_CLIENT_MQ_TCPIP);
      cf.setQueueManager("QM_thinkpad");
      cf.setChannel("SYSTEM.DEF.SVRCONN");

      MQQueueConnection connection = (MQQueueConnection) cf.createQueueConnection();
      MQQueueSession session = (MQQueueSession) connection.createQueueSession(false, Session.AUTO_ACKNOWLEDGE);
      MQQueue queue = (MQQueue) session.createQueue("queue:///Q1");
      MQQueueSender sender =  (MQQueueSender) session.createSender(queue);
      MQQueueReceiver receiver = (MQQueueReceiver) session.createReceiver(queue);      

      long uniqueNumber = System.currentTimeMillis() % 1000;
      JMSTextMessage message = (JMSTextMessage) session.createTextMessage("SimplePTP "+ uniqueNumber);     

      // Start the connection
      connection.start();

      sender.send(message);
      System.out.println("Sent message:\\n" + message);

      JMSMessage receivedMessage = (JMSMessage) receiver.receive(10000);
      System.out.println("\\nReceived message:\\n" + receivedMessage);

      sender.close();
      receiver.close();
      session.close();
      connection.close();

      System.out.println("\\nSUCCESS\\n");
    }
    catch (JMSException jmsex) {
      System.out.println(jmsex);
      System.out.println("\\nFAILURE\\n");
    }
    catch (Exception ex) {
      System.out.println(ex);
      System.out.println("\\nFAILURE\\n");
    }
  }