[英]Spring JMS can not connect to WebSphere MQ - authentication fail
我使用以下命令配置WebSphere MQ:
DEFINE QLOCAL(NEW.QL.RQ)
DEFINE QLOCAL(NEW.QL.RS)
DEFINE LISTENER('NEW.LSR') TRPTYPE(TCP) PORT(1420) CONTROL(QMGR)
START LISTENER('NEW.LSR')
DEFINE CHANNEL('NEW.SVR.CONN') CHLTYPE(SVRCONN)
SET CHLAUTH(*) TYPE(BLOCKUSER) USERLIST('nobody','*MQADMIN')
SET CHLAUTH(SYSTEM.ADMIN.*) TYPE(BLOCKUSER) USERLIST('nobody')
SET CHLAUTH(NEW.SVR.CONN) TYPE(ADDRESSMAP) ADDRESS(*) USERSRC(CHANNEL)
SET CHLAUTH(NEW.SVR.CONN) TYPE(BLOCKUSER) USERLIST('nobody')
REFRESH SECURITY
然后,我可以使用mqm
用戶名和空密碼使用MQ Explore成功連接到它。
但是,當我使用spring jms時,身份驗證失敗。 以下部分是我的xml配置。
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<context:property-placeholder location="classpath:main.properties" />
<!-- WebSphere MQ Connection Factory -->
<bean id="mqConnectionFactory" class="com.ibm.mq.jms.MQQueueConnectionFactory">
<property name="hostName">
<value>${queue_hostname}</value>
</property>
<property name="port">
<value>${queue_port}</value>
</property>
<property name="queueManager">
<value>${queue_manager}</value>
</property>
<property name="transportType">
<value>1</value>
</property>
</bean>
<bean id="jmsConnectionFactory"
class="org.springframework.jms.connection.UserCredentialsConnectionFactoryAdapter">
<property name="targetConnectionFactory" ref="mqConnectionFactory" />
<property name="username">
<value>${mq.username}</value>
</property>
<property name="password">
<value>${mq.password}</value>
</property>
</bean>
<!-- JMS Destination Resolver -->
<bean id="jmsDestinationResolver"
class="org.springframework.jms.support.destination.DynamicDestinationResolver">
</bean>
<!-- JMS Queue Template -->
<bean id="jmsQueueTemplate" class="org.springframework.jms.core.JmsTemplate102">
<property name="connectionFactory">
<ref bean="jmsConnectionFactory" />
</property>
<property name="destinationResolver">
<ref bean="jmsDestinationResolver" />
</property>
<property name="pubSubDomain">
<value>false</value>
</property>
<property name="receiveTimeout">
<value>20000</value>
</property>
</bean>
<bean id="messageService" class="com.test.testspringjmsmq.MessageService" />
</beans>
錯誤消息:
Caused by: com.ibm.msg.client.jms.DetailedJMSSecurityException: JMSWMQ2013: The security authentication was not valid that was supplied for QueueManager 'LOROL' with connection mode 'Client' and host name 'xx.xx.xx.xx'. Please check if the supplied username and password are correct on the QueueManager you are connecting to
at com.ibm.msg.client.wmq.common.internal.Reason.reasonToException(Reason.java:531)
at com.ibm.msg.client.wmq.common.internal.Reason.createException(Reason.java:219)
at com.ibm.msg.client.wmq.internal.WMQConnection.<init>(WMQConnection.java:410)
at com.ibm.msg.client.wmq.factories.WMQConnectionFactory.createV7ProviderConnection(WMQConnectionFactory.java:7855)
at com.ibm.msg.client.wmq.factories.WMQConnectionFactory.createProviderConnection(WMQConnectionFactory.java:7331)
at com.ibm.msg.client.jms.admin.JmsConnectionFactoryImpl.createConnection(JmsConnectionFactoryImpl.java:276)
at com.ibm.mq.jms.MQConnectionFactory.createCommonConnection(MQConnectionFactory.java:6055)
at com.ibm.mq.jms.MQTopicConnectionFactory.createTopicConnection(MQTopicConnectionFactory.java:114)
at com.ibm.mq.jms.MQTopicConnectionFactory.createConnection(MQTopicConnectionFactory.java:197)
at org.springframework.jms.connection.SingleConnectionFactory.doCreateConnection(SingleConnectionFactory.java:343)
at org.springframework.jms.connection.SingleConnectionFactory.initConnection(SingleConnectionFactory.java:290)
at org.springframework.jms.connection.SingleConnectionFactory.createConnection(SingleConnectionFactory.java:227)
at org.springframework.jms.support.JmsAccessor.createConnection(JmsAccessor.java:184)
at org.springframework.jms.core.JmsTemplate.execute(JmsTemplate.java:461)
... 25 more
Caused by: com.ibm.mq.MQException: JMSCMQ0001: WebSphere MQ call failed with compcode '2' ('MQCC_FAILED') reason '2035' ('MQRC_NOT_AUTHORIZED').
at com.ibm.msg.client.wmq.common.internal.Reason.createException(Reason.java:206)
... 37 more
最后,我不使用Spring JMS來實現Java和WebSphere MQ之間的連接。
我直接使用簡單的JMS來實現它,並且我認為配置比Spring JMS更容易。
以下部分是簡單jms的示例代碼。
try {
MQQueueConnectionFactory cf = new MQQueueConnectionFactory();
// Config
cf.setHostName("localhost");
cf.setPort(1414);
cf.setTransportType(JMSC.MQJMS_TP_CLIENT_MQ_TCPIP);
cf.setQueueManager("QM_thinkpad");
cf.setChannel("SYSTEM.DEF.SVRCONN");
MQQueueConnection connection = (MQQueueConnection) cf.createQueueConnection();
MQQueueSession session = (MQQueueSession) connection.createQueueSession(false, Session.AUTO_ACKNOWLEDGE);
MQQueue queue = (MQQueue) session.createQueue("queue:///Q1");
MQQueueSender sender = (MQQueueSender) session.createSender(queue);
MQQueueReceiver receiver = (MQQueueReceiver) session.createReceiver(queue);
long uniqueNumber = System.currentTimeMillis() % 1000;
JMSTextMessage message = (JMSTextMessage) session.createTextMessage("SimplePTP "+ uniqueNumber);
// Start the connection
connection.start();
sender.send(message);
System.out.println("Sent message:\\n" + message);
JMSMessage receivedMessage = (JMSMessage) receiver.receive(10000);
System.out.println("\\nReceived message:\\n" + receivedMessage);
sender.close();
receiver.close();
session.close();
connection.close();
System.out.println("\\nSUCCESS\\n");
}
catch (JMSException jmsex) {
System.out.println(jmsex);
System.out.println("\\nFAILURE\\n");
}
catch (Exception ex) {
System.out.println(ex);
System.out.println("\\nFAILURE\\n");
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.