[英]cant get a with a while loop inside a while loop to work
while loop == True: #creates loop, and uses previously defined 'loop'
try:
ans = int(input("What is the answer to " + str(num1) + " x " + str(num2) + " ? ")) #asks question and requires a user input
correct = (ans == num1 * num2)
if correct:
invtimer()
print("You are correct! ")
break #if the answer is correct, it prints 'You are correct!' and breaks to avoid the loop
else:
invtimer()
while loop == True:
showans = input('''Wrong answer.
Would you like to see the answer? (yes)(y)
or try again? (no)(n) ''')
if showans in ["yes", "y", "Yes", "Y"]:
invtimer()
print("The answer is " + str(num1 * num2) + "!")
break
elif showans in ["no", "n", "No", "N"]:
loop == False
else:
print("That is not an option! ")
loop == False
except ValueError:
print("That is not a number! ")
I need help with getting the second loop == False to link back the fist while loop. 我需要获得第二个循环== False的帮助才能将拳头的while循环连回。 when I run it, it keeps going back to the second while loop.
当我运行它时,它会一直回到第二个while循环。
You were using the ==
operator. 您正在使用
==
运算符。 This operator is only meant to be used in conditional statements and loops, not when assigning variables. 该运算符仅用于条件语句和循环,而不用于分配变量。 When you assign
False
to a variable use =
instead 当您将
False
赋给变量时,请使用=
代替
while loop == True: #creates loop, and uses previously defined 'loop'
try:
ans = int(input("What is the answer to " + str(num1) + " x " + str(num2) + " ? ")) #asks question and requires a user input
correct = (ans == num1 * num2)
if correct:
invtimer()
print("You are correct! ")
break #if the answer is correct, it prints 'You are correct!' and breaks to avoid the loop
else:
invtimer()
while loop == True:
showans = input('''Wrong answer.
Would you like to see the answer? (yes)(y)
or try again? (no)(n) ''')
if showans in ["yes", "y", "Yes", "Y"]:
invtimer()
print("The answer is " + str(num1 * num2) + "!")
break
elif showans in ["no", "n", "No", "N"]:
loop = False
else:
print("That is not an option! ")
loop = False
except ValueError:
print("That is not a number! ")
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