如何创建动作 <T> 形成通过反射给出的对象方法？

Question

I have a void SubscribeToPublish<TMessage>(Action<TMessage> action) method. And it expects an Action<T> . I have an object created purely from Type in a way like this:

var Node =  Activator.CreateInstance(type);
var methods = type.GetMethods(BindingFlags.Public).Where(methodInfo => methodInfo.GetParameters().Count() == 1).ToList();
methods.ForEach(methodInfo => {
    SubscribeToPublish(o => methodInfo.Invoke( pair.Value.Node, o )); // Here I see error cannot be inferred from usage.
});

Thus I wonder: how to create Action<T> on the go having objects created via Reflection?

Answer 1

methodInfo.Invoke accepts arbitrary object parameters. Thus, the compiler cannot infer which concrete TMessage type you mean.

The solution is to specify it explicitly:

SubscribeToPublish((MyMessage o) => methodInfo.Invoke(pair.Value.Node, 
                                                      new object[] {o}));