选择在a列中找到b列的行
[英]Select rows where column b is found in column a
问题描述
I have a table that looks like this... 
我有一张看起来像这样的桌子...
------------------------------------
| sku | superseded_sku |
------------------------------------
| PartA | PartC |
| PartB | PartC |
| PartC | PartD |
| PartD | |
I need to write a query that will show me all rows where an entry from coumn B appears in column A. For example here it would give me the following... 我需要编写一个查询，向我显示列A中列B条目出现的所有行。例如，在这里它将给我以下内容...
------------------------------------
| sku | superseded_sku |
------------------------------------
| PartC | PartD |
| PartD | |
I have tried this... 我已经尝试过了...
SELECT x.sku, x.superseded_sku FROM table x
JOIN table y ON y.sku = x.sku
WHERE y.superseded_sku = x.sku
but it returns nothing and now I don't know where to go from here 但它什么也没返回，现在我不知道从这里去哪里
1 个解决方案
解决方案1
0 已采纳 2015-03-31 09:34:26
Think this query will give you the result: 认为此查询将为您提供结果：
SELECT x.sku, x.superseded_sku FROM table x
JOIN table y ON y.sku = x.superseded_sku
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