如何在一个dicts列表中获得具有公共密钥最大值的整个dict

Question

I have a list of dicts like below:

lod = [
{'name': 'Tom', 'score': 60},
{'name': 'Tim', 'score': 70},
{'name': 'Tam', 'score': 80},
{'name': 'Tem', 'score': 90}
]

I want to get {'name': 'Tem', 'score':90} but I only can do below:

max(x['score'] for x in lod)

This only return the value 90 .

How can I get the whole dict?

Answer 1

You can use the key function of max :

>>> lod = [
... {'name': 'Tom', 'score': 60},
... {'name': 'Tim', 'score': 70},
... {'name': 'Tam', 'score': 80},
... {'name': 'Tem', 'score': 90}
... ]
... 
>>> max(lod, key=lambda x: x['score'])
{'name': 'Tem', 'score': 90}

Answer 2

Just pass your list to max , like this:

>>> from operator import itemgetter
>>> lod = [
... {'name': 'Tom', 'score': 60},
... {'name': 'Tim', 'score': 70},
... {'name': 'Tam', 'score': 80},
... {'name': 'Tem', 'score': 90}
... ]
>>> max(lod, key=itemgetter('score'))
{'score': 90, 'name': 'Tem'}

Answer 3

I dont know whether sorting is time consuming,

>>>sorted(lod, key=lambda x:x['score'])[-1]
{'name': 'Tem', 'score': 90}