如何在字典的字典中找到具有最高值的键？

Question

I have a dict of dicts.

Example:

scores[i][subentity_type] = the_score

It looks like this:

scores = {0:{'SD':1,'ED':2},1:{'SD':0.5,'ED':3}}

so i would want a function that returns

'SD' --> 0
'ED' --> 1

for each subentity_type , I want to find the key i with the highest score. do you have an idea if there is a python function to provide this? thanks!

Answer 1

There is a max() method that accepts an array and determines the max value.

You can turn the values of a dict into a list with mydict.values() or as a generator v for v in mydict.values() .

You however have a dict of dicts. You can iterate through it with for dictofdict in mydict.values()

-> Resulting code:

>>> mydict={'a': {'aa': 3, 'ab':7},
...         'b': {'ba': 5, 'bb':9}}
>>> [v for dictofdict in mydict.values() for v in dictofdict.values()]
[3, 7, 5, 9]
>>> max([v for dictofdict in mydict.values() for v in dictofdict.values()])
9

A dict of dict where you get the highest value.

Answer 2

Since you haven't actually explained how your final output should look like but I think you can sort the dict items based on values and get the key with highest value. Taking the example for Tin's answer

mydict={'a': {'aa': 3, 'ab':7},
        'b': {'ba': 5, 'bb':9}}

new_dict ={}

for k in mydict.keys():
    new_dict[k] = sorted(mydict[k].items(), key= lambda v:-v[1])[0][0] 

#new_dict = {'a': 'ab', 'b': 'bb'}