如何在yii2中显示相关表格中的数据？

Question

i got the problem when to display data from related table using yii2. I use my own design and not using from yii2 design. I have two tables user and state

TABLE `user`(
`user_id` int(11) NOT NULL auto_increment,
`state_id` int(11) null 

table `state`(
`state_id` int(11) NOT NULL auto_increment,
`state` varchar(225) null

UserModel.php

public function getStates()
{
    return $this->hasOne(State::className(),['state_id' =>'state_id']);
}

UserController.php

 public function actionView($id)
{
    return $this->render('view', [
        'model' => $this->findModel($id),

    ]);
}

State.php

 public function attributeLabels()
{
    return [
        'state_id' => 'State ID',
        'state' => 'State',
     ];
}

public function getState()
{
    return $this->state.'';
}

view.php

<table>..<tr>
    <td>Negeri</td>
    <td><?php echo $model->states; ?></td>
</tr>

when I use $model->states; I got the error when execute at the browser. The error is " Object of class app\\models\\State could not be converted to string ". Before I write that code, I use $model->state_id and the result is number value which is state_id attribute from table state. What I want is, the name of the state(state attribute from table state),not the state_id. If using yii2 design, the results will be displayed from what I want. That code its look like this::

<?= DetailView::widget([
    'model' => $model,
    'attributes' => [
        'states.state',

    ],
]) ?>  

So, my question is how to recall function getStates() from UserModel.php or getState() from state.php that I created to view.php and display data from related table? . sorry, if my english language not very well .

Answer 1

Since $model->states is an object, you should simply use :

<?= $model->states->state ?>

And you don't need getState() function in State model.