bash shell脚本在循环执行程序后终止

Question

The below simplified (printf/echo/cd/sleep/progressbar commands that do not matter left out) bash shell script terminates after the first execution of the binary. Why is this? Can I do or test anything without modifying the binary itself (Can only do this to certain limited extent) ?

PROGRESS=0
SIMULATIONS=30

for number in $(seq ${PROGRESS} ${SIMULATIONS})
  do
  echo 'INB4 TERMINATION'
  nohup ./binary -someflag
  # do other stuff next
  echo 'NEVER GETS HERE'
done

I have read up on traps but adding this line:

trap "echo 'trap invoked'; exit" SIGHUP SIGINT SIGTERM

• does not seem to work.
• Using nohup or not does not seem to matter.
• the loop works fine without the binary command.

what the binary does

It runs a 3D robot simulation experiment (which itself forks once to run 2 robot simulator processes in parallel (using the C/C++ system() command). Also each robot simulator launches a thread for each of 16 robot controllers). So the binary is the parent process of 32 threads. If that makes sense at all, does it matter?

Answer 1

I just found out what was causing it. I pulled a progress bar bash function from somewhere and called that function after the ./binary. This was causing my script to stop... I just didn't thought it was the cause earlier, because it didn't output anything. That was a stupid assumption.

For completeness, this is the progress bar I was using: https://github.com/fearside/ProgressBar/