[英]Plot bar graph from Pandas DataFrame
Assuming i have a DataFrame
that looks like this:假设我有一个看起来像这样的DataFrame
:
Hour | V1 | V2 | A1 | A2
0 | 15 | 13 | 25 | 37
1 | 26 | 52 | 21 | 45
2 | 18 | 45 | 45 | 25
3 | 65 | 38 | 98 | 14
Im trying to create a bar plot to compare columns V1
and V2
by the Hour
.我试图创建一个条形 plot 以按Hour
比较列V1
和V2
。 When I do:当我做:
import matplotlib.pyplot as plt
ax = df.plot(kind='bar', title ="V comp",figsize=(15,10),legend=True, fontsize=12)
ax.set_xlabel("Hour",fontsize=12)
ax.set_ylabel("V",fontsize=12)
I get a plot and a legend with all the columns' values and names.我得到一个 plot 和一个包含所有列的值和名称的图例。 How can I modify my code so the plot and legend only displays the columns V1
and V2
如何修改我的代码,以便 plot 和图例仅显示列V1
和V2
To plot just a selection of your columns you can select the columns of interest by passing a list to the subscript operator: 要仅绘制您选择的列,您可以通过将列表传递给下标运算符来选择感兴趣的列:
ax = df[['V1','V2']].plot(kind='bar', title ="V comp", figsize=(15, 10), legend=True, fontsize=12)
What you tried was df['V1','V2']
this will raise a KeyError
as correctly no column exists with that label, although it looks funny at first you have to consider that your are passing a list hence the double square brackets [[]]
. 您尝试过的操作是df['V1','V2']
这将引发KeyError
因为该标签没有正确的列,尽管起初看起来很可笑,您必须考虑传递列表,因此使用双方括号[[]]
。
import matplotlib.pyplot as plt
ax = df[['V1','V2']].plot(kind='bar', title ="V comp", figsize=(15, 10), legend=True, fontsize=12)
ax.set_xlabel("Hour", fontsize=12)
ax.set_ylabel("V", fontsize=12)
plt.show()
A minimal seaborn apporach to plot from pandas dataframe:从 pandas Z6A8064B5DF47945550DZ0553 到 plot 的最小 seaborn 方法
import pandas as pd
import seaborn as sns
random_dict = {
"classes": ["A", "B", "C"],
"quantities": [100, 300, 200]
}
df = pd.DataFrame.from_dict(random_dict)
sns.barplot(x="classes", y="quantities", data=df)
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