C ++指针语法->

Question

I was trying to understand what a->b referred to and I was able to understand it refers to

(*a).b

where a is a pointer. What does a->b->c mean in those terms - ie is it (*((*a).b)).c?

Answer 1

是的， a->b->c等效于(*(*a).b).c ，等效于(*((*a).b)).c 。