C ++中的指针（语法）

Question

I have some guesses I wish to confirm. I would be extremely grateful if someone could help me out.

When I declare a pointer in C++, for example

int *x = 5;

Does that mean that * is not for dereferencing, but just for declaration of the pointer; as a result, x is referring to the address of int x?

Thanks in advance.

Answer 1

You are almost correct, int *x (that you can also write int* x ) means that x is a pointer to an int... But there is not int liked to it yet

int *x = 5;

actually means that x is a pointer that is linked to memory address 5, which should contain an int. Since this address is probably not allocated by your program, this will likely fail.

You can try to do the following

int x = 5;
int *xAddr = &x;
*xAddr = 3;

Here we declared xAddr in the same way as you did, but telling it that it points to the address (that's the & character) of x; By changing the value that xAddr points to to 3 (line 3, here we are dereferencing), we change the value of x to 3

Here is a nice tutorial to understand pointers better