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从基准中选择时间作为UNIX_TIMESTAMP(time)laravel 5

[英]Select time from base as UNIX_TIMESTAMP(time) laravel 5

I have in base field with type datetime , it's time field. 我在类型为datetime基本字段中有time字段。 I want to get all elements from base and get additional timeu field - it's UNIX_TIMESTAMP(time) . 我想从base获取所有元素,并获取其他timeu字段-它是UNIX_TIMESTAMP(time) I try to do this by add ->select('*','UNIXTIMESTAMP(time) AS timeu') but Laravel gives me error. 我尝试通过添加->select('*','UNIXTIMESTAMP(time) AS timeu')来执行此操作,但是Laravel给了我错误。 I need it to use in ->keyBy() . 我需要它在->keyBy() I have next error: 我有下一个错误:

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'UNIX_TIMESTAMP(time)' in 'field list' (SQL: select *, `UNIX_TIMESTAMP(time)` as `timeu` from `values` where UNIX_TIMESTAMP(time) <= 1429135199 and UNIX_TIMESTAMP(time) >= 1428444000 order by `id` asc)

How can I fix it? 我该如何解决?

Laravel needs to know that UNIX_TIMESTAMP(time) as timeu is a RAW SQL expression and not a column name: Laravel需要知道UNIX_TIMESTAMP(time) as timeu是RAW SQL表达式,而不是列名:

->select('*', \DB::raw('UNIX_TIMESTAMP(time) AS timeu'))

Or alternatively: 或者:

->selectRaw('*, UNIX_TIMESTAMP(time) AS timeu')

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