如何显示今天的UNIX_TIMESTAMP中的所有记录

Question

I'm trying to display all attacks which have happened today. This is the current SQL I have in my php page. However it doesn't display how many have happened today.

$TodayAttacks = $odb->query("SELECT COUNT(id) FROM `logs` WHERE `date` BETWEEN DATE_SUB(CURDATE(), INTERVAL '-1' DAY) AND UNIX_TIMESTAMP()")->fetchColumn(0);

Answer 1

If by "today" you mean "since midnight today", your query should look something like this:

SELECT COUNT(id) FROM logs
 WHERE date >= CURDATE();

If there is a possibility of date values in the log greater than today's date (hey, weird stuff happens!) then you want this (I advise against using BETWEEN for date comparisons):

SELECT COUNT(id) FROM logs
 WHERE date >= CURDATE()
   AND date < DATE_ADD(CURDATE(), INTERVAL 1 DAY);

If you mean "within the last 24 hours", your query would look more like this:

SELECT COUNT(id) FROM logs
 WHERE date >= DATE_SUB(NOW(), INTERVAL 1 DAY);

Hope this helps.

EDITED per comments below

If the date column is a Unix timestamp value (stored as INT(11) ?) then the query should look something like the following:

SELECT COUNT(id) FROM logs
 WHERE date >= UNIX_TIMESTAMP(CURDATE());

One could also do the following to get records from the last 24 hours:

SELECT COUNT(id) FROM logs
 WHERE date >= UNIX_TIMESTAMP(DATE_SUB(NOW(), INTERVAL 1 DAY));

SQL Fiddle here .