如何在某个字符串后剥离所有内容

Question

basically I want to turn something like this

FlorenceBuilding04_geometry_clean_001_Loc1_position

to

/root/world/geo/FlorenceBuilding04_model_geometry

and

FlorenceBuilding05_geometry1_clean_001_Loc1_position

to

/root/world/geo/FlorenceBuilding05_model_geometry

Code:

s = GetName()
if s.endswith( "_position" ):
    rootname = "/root/world/geo/"+s[ :- 18 ].rstrip("_")
    rootname =rootname.replace("geometry","model_geometry")

thanks in advance

Answer 1

And you could do this also:

>>> a = 'FlorenceBuilding04_geometry_clean_001_Loc1_position'
>>> path = '/root/world/geo/' + a.split('geometry')[0] + 'model_geometry'
>>> print(path)
/root/world/geo/FlorenceBuilding04_model_geometry

Answer 2

You aren't very specific about the criteria, but it seems like you want to keep the first part up to "_geometry" and discard everthing else. That is easily done with index :

>>> def convert(example):
...     print "/root/world/geo/%s_model_geometry" % example[:example.find("_geometry")]
... 
>>> convert("FlorenceBuilding04_geometry_clean_001_Loc1_position")
/root/world/geo/FlorenceBuilding04_model_geometry
>>> convert("FlorenceBuilding05_geometry1_clean_001_Loc1_position")
/root/world/geo/FlorenceBuilding05_model_geometry