我如何在正则表达式及其之后的所有内容中拆分

Question

I have a Regex that successfully captures a date. Now I wanna split it so that everything after the date is also taken. I have this now:

data = "11/07/2020 apple\n juice\n 11/07/2020 pear"
dateRegex = re.compile('([0-9]+\/[0-9]+\/[0-9]+)')
splittedData = re.split(dateRegex, data)

# Splits into: ['11/07/2020', ' apple\n juice\n ', '11/07/2020' ' pear']
# Desired:     ['11/07/2020 apple\n juice\n ', '11/07/2020 pear']

Thanks in advance.

Answer 1

You can use

(?<=\s)(?=\d+/\d+/\d+)

NOTE : Works with re.split in Python 3.7 and newer where the support of splitting on a pattern that could match an empty string was added.

Details

• (?<=\\s) - a location immediately preceded with a whitespace
• (?=\\d+/\\d+/\\d+) - a location immediately followed with 1+ digits and two occurrences of / + one or more digits.

See the Python demo :

import re
data = "11/07/2020 apple\n juice\n 11/07/2020 pear"
dateRegex = re.compile('(?<=\s)(?=\d+/\d+/\d+)')
splittedData = re.split(dateRegex, data)
print(splittedData)
# => ['11/07/2020 apple\n juice\n ', '11/07/2020 pear']