[英]bash while loop using echo as the loop counter
hello I have a command 你好,我有一个命令
echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')
this returns a integer value I need to while loop over it but can't seem to figure out who to do that. 这返回一个整数值,我需要在while循环上遍历,但似乎无法弄清楚是谁做的。
while echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l') -g 1; do
echo stuff
done
Hi You can try like this, 嗨,您可以尝试这样,
declare -i value
value=`echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')`
while [ "$value" -gt 1 ]; do
echo stuff
value=`echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')`
done
OR we can use it like, 或者我们可以像这样使用它,
declare -i value
while : ; do
value=`echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')`
[[ "$value" -gt 1 ]] || break
echo stuff
done
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