bash while loop using echo as the loop counter

Question

hello I have a command

echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')

this returns a integer value I need to while loop over it but can't seem to figure out who to do that.

while echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l') -g 1; do

echo stuff

done

Answer 1

Hi You can try like this,

declare -i value
value=`echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')`
while [ "$value" -gt 1 ]; do
    echo stuff
    value=`echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')`
done

OR we can use it like,

declare -i value
while : ; do
  value=`echo $(ssh dema@10.0.1.100 'zfs list -o name -t snapshot | grep tank/dema@Daily_$(date +"%Y-%m-%d") | wc -l')`
  [[ "$value" -gt 1 ]] || break
  echo stuff
done