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用系数重新采样熊猫数据框

[英]Resample a Pandas dataframe with coefficients

I have a data frame with the following columns: {'day','measurement'} 我有一个包含以下列的数据框: {'day','measurement'}

And there might be several measurements in a day (or no measurements at all) 一天可能有几次测量(或完全没有测量)

For example: 例如:

day     |    measurement
1       |     20.1
1       |     20.9
3       |     19.2
4       |     20.0
4       |     20.2

and an array of coefficients: coef={-1:0.2, 0:0.6, 1:0.2} 以及系数数组: coef={-1:0.2, 0:0.6, 1:0.2}

My goal is to resample the data and average it using the coefficiets, (missing data should be left out). 我的目标是对数据进行重新采样并使用系数进行平均(应该省略缺失的数据)。

This is the code I wrote to calculate that 这是我写来计算的代码

window=[-1,0,-1]
df['resampled_measurement'][df['day']==d]=[coef[i]*df['measurement'][df['day']==d-i].mean() for i in window if df['measurement'][df['day']==d-i].shape[0]>0].sum()
df['resampled_measurement'][df['day']==d]/=[coef[i] for i in window if df['measurement'][df['day']==d-i].shape[0]>0].sum()

For the example above, the output should be: 对于上面的示例,输出应为:

Day  measurement
1    20.500
2    19.850
3    19.425
4    19.875

The problem is that the code runs forever, and I'm pretty sure that there's a better way to resample with coefficients. 问题是代码可以永远运行,而且我很确定有更好的方法对系数进行重采样。

Any advice would be highly appreciated ! 任何建议将不胜感激!

Here's a possible solution to what you're looking for: 以下是您要寻找的解决方案:

        # This is your data
In [2]: data = pd.DataFrame({
   ...:     'day': [1, 1, 3, 4, 4],
   ...:     'measurement': [20.1, 20.9, 19.2, 20.0, 20.2]
   ...: })

        # Pre-compute every day's average, filling the gaps
In [3]: measurement = data.groupby('day')['measurement'].mean()

In [4]: measurement = measurement.reindex(pd.np.arange(data.day.min(), data.day.max() + 1))

In [5]: coef = pd.Series({-1: 0.2, 0: 0.6, 1: 0.2})

        # Create a matrix with the time-shifted measurements
In [6]: matrix = pd.DataFrame({key: measurement.shift(key) for key, val in coef.iteritems()})

In [7]: matrix
Out[7]:
       -1     0     1
day
1     NaN  20.5   NaN
2    19.2   NaN  20.5
3    20.1  19.2   NaN
4     NaN  20.1  19.2

        # Take a weighted average of the matrix
In [8]: (matrix * coef).sum(axis=1) / (matrix.notnull() * coef).sum(axis=1)
Out[8]:
day
1    20.500
2    19.850
3    19.425
4    19.875
dtype: float64

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