使用带有字符的数组时，要级联的矩阵的维数不一致

Question

I'm trying to initialize

labels =['dh';'Dh';'gj';'Gj';'ll';'Ll';'nj';'Nj';'rr';'Rr';'sh';'Sh';'th';'Th';'xh';'Xh';'zh';'Zh';'ç';'Ç';'ë';'Ë'];

But it shows me the error on title.When I try with numbers it's all perfect but not with characters.What could be the problem?

Answer 1

If you wish to eliminate any padding, you can also store it into a cell as follows.

labels = {'dh';'Dh';'gj';'Gj';
         'll';'Ll';'nj';'Nj';
         'rr';'Rr';'sh';'Sh';
         'th';'Th';'xh';'Xh';
         'zh';'Zh';'ç';'Ç';
         'ë';'Ë'};

Then you can reference the "i"th element using labels{i} instead of labels(i,:) which is simpler. You can further run more string operations using cellfun and not interfere with any existing values that you've stored.

Answer 2

I agree with krisdestruction that using a cell array makes the code accessing the strings simpler and is generally more idiomatic. That is what I would also recommend unless there is a compelling reason to do something else.

For completeness, you could use the char function to add the padding automatically for you if you really want a character array:

>> char('aa','bb','c')

ans =

aa
bb
c 

where the last row is 'c ' . From the char documentation:

S = char(A1,...,AN) converts the arrays A1,...,AN into a single character array. After conversion to characters, the input arrays become rows in S. Each row is automatically padded with blanks as needed . An empty string becomes a row of blanks.

(Emphasis mine)

Answer 3

From the Mathworks documentation :

Apply the MATLAB concatenation operator, []. Separate each row with a semicolon (;). Each row must contain the same number of characters . For example, combine three strings of equal length:

You can try padding like this to make every row 2 characters:

labels = ['dh';'Dh';'gj';'Gj';
         'll';'Ll';'nj';'Nj';
         'rr';'Rr';'sh';'Sh';
         'th';'Th';'xh';'Xh';
         'zh';'Zh';'ç ';'Ç ';
         'ë ';'Ë '];