如何用正则表达式匹配特定的字符串？

Question

I have a string

var txt="[!Qtextara1] Description1 [@Qtextara1]
        [!Qtextarea2] Description2 [@Qtextarea2]"

I want to match this string using regular expression The output should something like this.

{Qtextara1: Description1,  Qtextarea2: Description2} 

Is it possible with regular expression? Please help me..
Thanks in advance.

Answer 1

You can use the following regex:

\[\!([\s\S]+?)\]\s+([\s\S]+?)\s*\[@\1\]

Explanation:

• \\[\\! - Match literal [!
• ([\\s\\S]+?) - Capture group 1 to match 1 or more characters inside [] (the tag name, we'll need that later on)
• \\]\\s+ - Literal ] and 1 or more whitespace symbols
• ([\\s\\S]+?) - Capture group 2 to capture (even multiline) description
• \\s*\\[@\\1\\] - Match 0 or more whitespace, followed by a literal [@ , then a backreference to the first capture group (the tag name), and then a literal ] .

See demo .

 var re = /\\[\\!([\\s\\S]+?)\\]\\s+([\\s\\S]+?)\\s*\\[@\\1\\]/g; var test_str = '[!Qtextara1] Long Description Wi[th%^&*\\n(Abra# $]Cadabra~!~## 1 [@Qtextara1]\\n [!Qtextarea2] Description2 [@Qtextarea2]'; while ((m = re.exec(test_str)) !== null) { alert(m[1] + ", " + m[2]) } 

Answer 2

I got this

txt.match(/(\[\![a-zA-Z0-9]*\]) ([a-zA-Z0-9]*) (\[\@[a-zA-Z0-9]*\])/);

That split in 3 part:

Part 1 :

txt.match(/(\[\![a-zA-Z0-9]*\]) ([a-zA-Z0-9]*) (\[\@[a-zA-Z0-9]*\])/)[1];
"[!Qtextara1]"

Part 2 :

txt.match(/(\[\![a-zA-Z0-9]*\]) ([a-zA-Z0-9]*) (\[\@[a-zA-Z0-9]*\])/)[2];
"Description1"

Part 3 :

txt.match(/(\[\![a-zA-Z0-9]*\]) ([a-zA-Z0-9]*) (\[\@[a-zA-Z0-9]*\])/)[3];
"[@Qtextara1]"

But that could be greatly improved.