在Prolog中打印出List的元素

Question

I've got a list, X, that contains three elements; ID, Name, and Grade. All taken from user input

read_student_info([A, B, C]),
nl, nl, menu([[A, B, C] | X]).

read_student_info([A, B, C]) :-
  write('\tStudent ID: '),
  read(A),
  write('\tStudent Name: '),
  read(B),
  write('\tStudent Grade: '),
  read(C).

Now, I want to display the elements from the list. So if I have a student whose ID = 3, Name = Tom, Grade = 78. That's what I'd like to print out. The current function I've been fooling around with is this:

show_records(X) :-
  X = [A | B],
  A = [C | D],
  id = write(C),
  name = format("~s", [B]),
  grade = write(D),
  show_records(B).

However I'll be the first to admit I have almost no clue what I'm doing. Any help would be very appreciated!

Answer 1

just suggesting a way to cleanup:

show_records([]).
show_records([A|B]) :-
  format('ID = ~w\tName = ~w\tGrade = ~w~n',A),
  show_records(B).

test:

?- show_records([[1,abel,10], [2,goofy,4]]).
ID = 1  Name = abel Grade = 10
ID = 2  Name = goofy    Grade = 4

clearly, tabs are not optimal, but simple to use

Answer 2

I have it figured out, mostly anyway. Here is my revision.

show_records(X) :-
X = [A | B],
write('\tID = '),
A = [C | D],
write(C),
write('\tName = '),
D = [E | F],
format("~s", [E]),
write('\tGrade = '),
F = [G | H],
write(G),
nl,
show_records(B).