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Neo4j Cypher:通过与另一个节点的关系对节点进行分组

[英]Neo4j Cypher: Group nodes by the relation to another node

Having a graph like post-->category , how can I get one post per category? 有一个像post-->category这样的图表,我怎样才能为每个类别发一个帖子?

ie: 即:

Having
    Post A1 --> Category A
    Post A2 --> Category A
    Post B1 --> Category B
    Post B2 --> Category B
    Post B3 --> Category B
    Post C1 --> Category C

I should get Post A2, Post B1, Post C1. 

I don't mind what post I get for a given category, just to get one for each category. 我不介意给出一个给定类别的帖子,只为每个类别获得一个。

Thanks! 谢谢!

To pick a post per category by random: 要随机选择每个类别的帖子:

MATCH (p:Post)-[:HAS_CATEGORY]->(c:Category)
WITH c, collect(p) as posts
RETURN c, posts[toInt(rand()*length(posts))]

We're using the collect aggregation function per category and in the return we pick one entry by random. 我们使用每个类别的collect聚合函数,并在返回时我们随机选择一个条目。

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