正则表达式搜索并替换Python中的子字符串

Question

I need some help with a regular expression in python. 我需要一些有关python中的正则表达式的帮助。

I have a string like this: 我有一个像这样的字符串：

>>> s = '[i1]scale=-2:givenHeight_1[o1];'

How can I remove givenHeight_1 and turn the string to this? 如何删除givenHeight_1并将字符串转换为此？

>>> '[i1]scale=-2:360[o1];'

Is there an efficient one-liner regex for such a job? 是否有有效的单行正则表达式来完成这项工作？

UPDATE 1: my regex so far is something like this but currently not working: 更新1：到目前为止，我的正则表达式是这样的，但目前无法正常工作：

re.sub('givenHeight_1[o1]', '360[o1]', s)

Answer 1

You can use positive look around with re.sub : 您可以对re.sub使用正面look around ：

>>> s = '[i1]scale=-2:givenHeight_1[o1];'
>>> re.sub(r'(?<=:).*(?=\[)','360',s)
'[i1]scale=-2:360[o1];'

The preceding regex will replace any thing that came after : and before [ with an '360' . 前面的正则表达式将取代来到之后的任何事情:之前[用'360' 。

Or based on your need you can use str.replace directly : 或者根据您的需要，可以直接使用str.replace ：

>>> s.replace('givenHeight_1','360')
'[i1]scale=-2:360[o1];'