Sequelize：Include.where 按“父”模型属性过滤

Question

I have two Models related, Catalog and ProductCategory. The latter has a composed PK, 'id, language_id'. Here are the models simplified:

var Catalog = sequelize.define("Catalog", {
id: {
  type: DataTypes.INTEGER,
  primaryKey: true,
  autoIncrement: true
},
user_id: {
  type: DataTypes.INTEGER,
  allowNull: false
},
product_category_id: {
  type: DataTypes.STRING(7)
},
language_id: {
  type: DataTypes.INTEGER
},  
... more stuff ...
}

var ProductCategory = sequelize.define("ProductCategory", {
id: {
  type: DataTypes.STRING(7),
  primaryKey: true
},
language_id: {
  type: DataTypes.INTEGER,
  primaryKey: true
},
... more stuff ...
}

Catalog.belongsTo(models.ProductCategory, {foreignKey: 'product_category_id'});

I'm trying to include some info from ProductCategory table related to Catalog, but ONLY when the language_id matches.

At the moment I'm getting all the possible matches from both tables. This is the query right now:

Catalog.find({where:
    {id: itemId},
    include: {
        model: models.ProductCategory, 
        where: {language_id: /* Catalog.language_id */}
    }
})

Is there a way to use an attribute from Catalog to filter the include where both models have the same language?

By the way, I've also tried changing the where clause, without any consecuence:

where: {'ProductCategory.language_id': 'Catalog.language_id'}

Answer 1

Sequelize provides an extra operator $col for this case so you don't have to use sequelize.literal('...') (which is more a hack).

In your example the usage would look like this:

Catalog.find({where:
    {id: itemId},
    include: {
        model: models.ProductCategory, 
        where: {
          language_id: {$col: 'Catalog.language_id'}
        }
    }
})

Answer 2

You can try this (Especially if you are using MariaDB) -

const Sequelize = require('sequelize'); 
const op = Sequelize.Op;

Catalog.find({where:
    {id: itemId},
    include: {
        model: models.ProductCategory, 
        where: {
          language_id: {[op.col]: 'Catalog.language_id'}
        }
    }
})

Answer 3

这似乎可以解决问题：

where: {language_id: models.sequelize.literal('Catalog.language_id')}

Answer 4

Or even just try this:

const models = require("models directory");
    {
       model: models.ModelName,
       where: {
            column-name: column-value
         }
    }