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有没有办法在 where: $or 子句中包含一个数组?

[英]Is there a way to include an array in a where: $or clause with sequelize?

I have a array of Ids teamsIdsSelected = ['1', '5', .., 'X']我有一组 Ids teamsIdsSelected = ['1', '5', .., 'X']

Then, from my table named 'Challenge' I want to get all the the challenges that are linked to each teamId from the array teamsIdsSelected.然后,从名为“挑战”的表中,我想从数组 teamIdsSelected 中获取与每个 teamId 相关联的所有挑战。 So far, this is what I tried:到目前为止,这是我尝试过的:

  1. Using this function:使用此功能:
    createWhereClause(column, field) {
        return models.sequelize.where(
            models.sequelize.literal(`${column} in (`),
            `'${field}'`,
            models.sequelize.literal(')'))
    },
  1. Getting the challenges this way:以这种方式应对挑战:
    const challenges = await Challenge.findAndCountAll({
        where: {
            team_id: createWhereClause(team_id, teamsIdsSelected)
        }
    })

But it doesn't work, I only obtain the challenge with team_id equal to the last item of teamsIdsSelected = teamsIdsSelected.slice(-1)[0] For instance if teamsIdsSelected = ['1', '4', '7'] , the where clause at the end (when I look at the log) is only "where challenge.team_id = 7" .但它不起作用,我只获得 team_id 等于teamsIdsSelected = teamsIdsSelected.slice(-1)[0]的最后一项的挑战,例如如果teamsIdsSelected = ['1', '4', '7'] ,最后的 where 子句(当我查看日志时)只是"where challenge.team_id = 7"

What I would actually like is an OR condition that would take all challenges that match either 1, 4, or 7 as a team_id.我真正想要的是一个 OR 条件,它将所有与 1、4 或 7 匹配的挑战作为 team_id。 Is there a fast way to do it without creating a for loop ?有没有一种快速的方法可以在不创建 for 循环的情况下做到这一点?

Let me know if you need more precision about my issue.如果您需要更精确地了解我的问题,请告诉我。 Thanks.谢谢。

const challenges = await Challenge.findAndCountAll({
    where: {
        team_id: { [Op.in]: teamsIdsSelected }
    }
})

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