Is there a way to include an array in a where: $or clause with sequelize?

Question

I have a array of Ids teamsIdsSelected = ['1', '5', .., 'X']

Then, from my table named 'Challenge' I want to get all the the challenges that are linked to each teamId from the array teamsIdsSelected. So far, this is what I tried:

1. Using this function:

    createWhereClause(column, field) {
        return models.sequelize.where(
            models.sequelize.literal(`${column} in (`),
            `'${field}'`,
            models.sequelize.literal(')'))
    },

2. Getting the challenges this way:

    const challenges = await Challenge.findAndCountAll({
        where: {
            team_id: createWhereClause(team_id, teamsIdsSelected)
        }
    })

But it doesn't work, I only obtain the challenge with team_id equal to the last item of teamsIdsSelected = teamsIdsSelected.slice(-1)[0] For instance if teamsIdsSelected = ['1', '4', '7'] , the where clause at the end (when I look at the log) is only "where challenge.team_id = 7" .

What I would actually like is an OR condition that would take all challenges that match either 1, 4, or 7 as a team_id. Is there a fast way to do it without creating a for loop ?

Let me know if you need more precision about my issue. Thanks.

Answer 1

const challenges = await Challenge.findAndCountAll({
    where: {
        team_id: { [Op.in]: teamsIdsSelected }
    }
})